pub broadcast proof fn lemma_seq_two_subranges_index<A>(
s: Seq<A>,
j: int,
k1: int,
k2: int,
i: int,
)Expand description
requires
0 <= j <= k1 <= s.len(),0 <= j <= k2 <= s.len(),0 <= i < k1 - j,0 <= i < k2 - j,ensures#[trigger] s.subrange(j, k1)[i] == (#[trigger] s.subrange(j, k2))[i],